Because, while Switzerland is not part of the EU, it follows many of its regulations. Maybe even most of them.
In this particular case, I happen to know that the inofficial rule is indeed to have burner phones for travel into the us in some cases. But you're never supposed to have unencrypted data on your phone or laptop in any case.
EVEN IN DEATH I SERVE THE ~~OMNISSIAH~~ORNITHOLOGIST
Probably every single person with knee problems.
> binom.test(11,n=24, alternative = "two.sided")
Exact binomial test
data: 11 and 24
number of successes = 11, number of trials = 24, p-value = 0.8388
alternative hypothesis: true probability of success is not equal to 0.5
95 percent confidence interval:
0.2555302 0.6717919
sample estimates:
probability of success
0.4583333
Probably not. Or at least we can't conclude that from the data. ¯\_(ツ)_/¯
I didn't know that Rómendacil II was born with another name. Got the rest. :)
Logicians are mathematicians. Well, most of them are.
I have yet to meet a single logician, american or otherwise, who would use the definition without 0.
That said, it seems to depend on the field. I think I've had this discussion with a friend working in analysis.
VERSCHLAFEN
But the vector space of (all) real functions is a completely different beast from the space of computable functions on finite-precision numbers. If you restrict the equality of these functions to their extension,
defined as f = g iff forall x\in R: f(x)=g(x),
then that vector space appears to be not only finite dimensional, but in fact finite. Otherwise you probably get a countably infinite dimensional vector space indexed by lambda terms (or whatever formalism you prefer.) But nothing like the space which contains vectors like
F_{x_0}(x) := (1 if x = x_0; 0 otherwise)
where x_0 is uncomputable.
Functions from the reals to the reals are an example of a vector space with elements which can not be represented as a list of numbers.
Or more likely torus-earthers, unless the gluing is reversed.
Mäu