this post was submitted on 15 May 2025
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[–] [email protected] 16 points 1 month ago (12 children)
[–] [email protected] 10 points 1 month ago* (last edited 1 month ago) (11 children)

Equal sides in a triangle are only possible if the corners are equal. So, 60⁰ each.

But its height cannot be half of base because of the same Pythagorean theorem

(1,5)²+(1,5/2)²=2,8125

sqrt(2,8125) ≈ 1,677, which is half of a diagonal

So, we get 4 sides that are 1,5 in a parallelogram, but diagonals are 1,5 and 3,354, as opposed to both being 1,5 as shown on the picture

TL;DR: Won't work because Pythagorean theorem

[–] [email protected] 3 points 1 month ago (7 children)
[–] [email protected] 1 points 1 month ago (1 children)
[–] [email protected] 8 points 1 month ago (2 children)

They could each be on the vertices of a tetrahedron for all we know...

[–] [email protected] 3 points 1 month ago (1 children)

We do know that, with those measurements, they aren't confined to a single (Euclidean) plane.

[–] [email protected] 2 points 1 month ago* (last edited 1 month ago)

Exactly! I regret that I have but one upvote to give.

[–] [email protected] 2 points 1 month ago

I was thinking of plane surfaces, but if their altitudes are different, I guess it'd be possible.

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